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By subbing in a=1 b=1 and c=-6 into the quadratic formula, you should get two solutions of x which are x = 2 and x = -3
Concentrate on the x^2+4x. Halve the 4 or any number that occupies that space. Equals 2 in this case. Put (x+2)^2 and that is your first term. Expand the brackets= x^2 + 4x + 4. Don't want the extra + 4 a...
(7/2) - 72(7/2) - (98/2)= -(91/2)
With a question like this. Firstly you have to read it, of course. But more importantly you have to understand what it is asking of you. So it is asking to find the area with boundaries at x=2 and the y a...
To find the mean, we add all the numbers and divide by how many numbers there are. 15+9+12+13+6+15+18+10+11+21 = 130130/10 = 13The mean is 13.To find the median, we first arrange the numbers into order: ...
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