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Show that (x+1)(x+2)(x+3) can be written as ax^3+bx^2+cx+d

Start by multiplying any 2 brackets together: (x + 1)(x + 2): Split the 1st bracket: x(x+2) + 1(x+2) = x^2 + 2x + x + 2 = x^2 + 3x + 2 Then multiply that answer with the last bracket: (x + 3)(x^2 + 3x + 2...

Answered by Rushab S. Maths tutor
2869 Views

A solution to the equation 2x^2-3x-17=0 lies between 2&3 use method of trail and improvement to find the solution

Sub 2.5 into equation
it returns 6.75 so x<2.5
sub 2.25
it returns -0.96875 so 2.25<x<2.5
sub 2.4
it returns 3.448 so 2.25<x<2.4
sub 2.3
it returns 0.434...

Answered by Daniel C. Maths tutor
2890 Views

Please solve (x+3)(x+4)=20 for x

Expand the double bracket (x+3)(x+4) first: 1) (x)(x)= x^2, 2) (x)(4)=4x ,3) (3)(x)=3x, 4) (3)(4)=12write expanded equation:x^2+4x+3x+12=20simplify and equate the right hand side to zero:x^2+7x-8=0solve f...

Answered by Caitilin M. Maths tutor
2042 Views

Please expand this equation and simplify: (2x + 5)(9x -4)

There are 4 multiplication equations that need to be done:1) (2x) x (9x) = 18x22) (2x) x (-4) = -8x3) (5) x (9x) = 45x4) (5) x (-4) = -20Write this out as an equation: 18x2 - 8x + 45...

Answered by Lizkerry O. Maths tutor
2481 Views

Find the roots of the quadratic equation 2x^2 - 15x - 8

First we have to multiply 8 and 2 together to get 16. We then need to find all the factors for this number.These are:1 and 162 and 84 and 4 From these sets of factors, we have to find which has a differen...

Answered by Siobhan G. Maths tutor
4018 Views

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