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The equation of a curve is y = ax^2 + 3x + c where a and b are integers. The curve has a minimum point at (1,1), find a and c

We start by trying to find out the values of a and c using the information about the minimum point. We know we can rearrange the right hand side by completing the square: y = a(x^2 + 3x)+cy = a(x+3/2a)^2+...

Answered by Larbi E. Maths tutor
2228 Views

Find the derivative of yx+5y-sin(y) = x

When differentiating an expression of x and y we can use implicit differentiation when terms contain the y variable, recall that this is essentially differentiating the y term by y and then multiplying by...

Answered by Larbi E. Maths tutor
2470 Views

solve x^2 >3(x+6) (4 mks)

x2>3(x+6)Firsty expand brackets --> x2>3x+18Then make one side = to 0 ---> x2-3x-18>0Solve the quadratic (x+3)(x-6)>0find the solutions when =0 x=-3 and ...

Answered by Lucy C. Maths tutor
2052 Views

How can the y=sin(x) graph be manipulated?

First, lets sketch a simple y=sin(x) graph between 0 and 2Pi radians.There are 4 different places a number could be put into this equation to affect the y=sin(x) graph.y=2sin(x) will stretch the graph to ...

Answered by Maths tutor
3916 Views

Differentiate y=x^3ln2x

PRODUCT RULETherefore dy/dx=(x^3)(1/2x)(2)+(ln2x)(3x^2)=x^2+3x^2ln2x

Answered by Hannah A. Maths tutor
4044 Views

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