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This can be solved in two ways, by substitution or by elimination.Firstly, by substitution, rearrange the first of the two equations in terms of x by subtracting 2y from both sides to get x=4-2y. Then plu...

you would first change the equaton into the circle equation therefore completing the square (x -2)^2 -4 + (y + 5)^2 -25 = know use the equation to deduce the center of the circle (x -2)^2 + (y + 5)^2 = ...

dy/dx = 2x -2 - 12x^-0.5d^2/dx^2 = 2 + 6 x^-3/2

Solving this equation would mean finding the values of x that satisfy it equating to zero. Therefore, to start, you must simplify the equation by expanding all the values to get (x^2-2x+1)-(2x-2)-3=0 [exp...

While this equation may look complicated, it's actually much easier than it looks - this equation is called a hidden quadratic. This is because it can be rewritten and solved the same way you would solve ...