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Solve the equation x^6 + 26x^3 − 27 = 0

While this equation may look complicated, it's actually much easier than it looks - this equation is called a hidden quadratic. This is because it can be rewritten and solved the same way you would solve ...

SP
Answered by Saachi P. Maths tutor
5232 Views

Find the equation of the normal to the curve 2x^3+3xy+2/y=0 at the point (1,-1)

Step 1 Use Implicit differentiation with respect to x and y - 6x^2+3y + 3x(dy/dx) - 2/y^2(dy/dx) = 0Step 2 Write the equation as dy/dx =... - dy/dx = (6x^2 + 3y)/(2/y^2 - 3x)Step 3 Input (1,-1) into th...

Answered by Maths tutor
3132 Views

Solve the following equation: 13y - 5 = 9y + 27

13y - 5 = 9y + 2713y - 9y = 27 + 54y = 32y = 32/4y = 8

MG
Answered by Megan G. Maths tutor
3427 Views

Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.

(y-5)2 + y2 = 13y2-10y +25 + y2=13.2y2-10y+12=0.y2-5y+6=0.(y-3)(y-2)=0. So, y=3 or y=2. Then substituting these values of y back into x=y-...

HD
Answered by Hollie D. Maths tutor
5047 Views

Find the exact value of the integral of (2+7/x), between x=1 and x=e. Give your answer in terms of e.

1.) Find the integral of each term. --> [2x +7ln(x)]. --> Uses standard integrals--> e.g. that the integral of 1/x is ln(x).
2.) substitute values into the integral. --> [2(e)+ 7ln(e)]-...

Answered by Maths tutor
3563 Views

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