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Find the tangent to the curve y=x^2 +2x at point (1,3)

In order to find the gradient we need to differentiate d/Dx = 2x + 2using our point, the gradient is 4using y = mx+cy = 4x +cusing our pointsy= 4x - 1

Answered by Diana W. Maths tutor
2279 Views

Factorise fully x^3 - 10x^2 + 16x

The first thing we notice is that there is a common factor of x. Thus we can factor it out and get:x(x^2 - 10x + 16)
This becomes much easier to deal with. We now focus on the equation in the bracket...

Answered by Karina T. Maths tutor
2682 Views

What are the limits of an inverse tan graph.

pi/2 and -pi/2

Answered by Emily H. Maths tutor
2785 Views

Expand the brackets to create an equation. (2x+7)(x-3)

shown using a diagram during interview
using the crab claw method, multiplying the correct components with one another, displaying how to set it out neatly and correctly to the benefit of th...

Answered by James F. Maths tutor
1349 Views

16cos30° - 5tan60° = √x. Find the value of x.

Split up the two terms: cos30° = (1/2)√3 and tan60° = √3 (from memorised values of cos and tan)Therefore 16cos30° = 8√3 and 5tan60° = 5√3 8√3 - 5√3 = 3√3 = √9 x √3 = √27x=27

Answered by David G. Maths tutor
2231 Views

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