Top answers

Maths
All levels

Bob goes on a run. He runs at a constant speed of 5m/s for 30 minutes. How far does he run?

we know that distance = speed x time, so we should multiply the time (in seconds) by the speed that Bob runs. So Bob runs a distance of 5 x (30x60) = 5x1800 = 9000m (or 9km)

Answered by Adam R. Maths tutor
2400 Views

f(x)=cos(x), g(x)=2+cos(x-1), state g(x) as a vector applied to f(x)

First of all, look at what has happened to the y co ordinates, they have all been moved up by 2 units. Now consider the x co ordinates, they have been shifted to the right by 1 unit. So the vector is 1 2<...

Answered by Rachel M. Maths tutor
1905 Views

Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

5x + y = 21x - 3y = 9First, find the lowest common multiple for x or y and make the equations equal for either x or y.Here, we multiply the second equation by 5 to make the amount of x the same. The equat...

Answered by Sophia P. Maths tutor
3301 Views

Given that f(x ) = 4x^3 + 12, evaluate f ( −2) .

In this question we are looking to find a value by substitution. In this case we are substituting the integer (-2) into the equation in place of the x which would be illustrated as f(-2)= 4(-2)^3+12. It i...

Answered by Mikele P. Maths tutor
2536 Views

Solve x^3+2*x^2-5*x-6=0

First find a root of the function: f(x)=x^3+2x^2-5x-6 f(2)=(2)^3+2*(2)^2-5*(2)-6 =0. Therefore, (x-2)(x^2+Ax+3)=0 where A is an unkown constant. Compare x^2 coeffecients: A-2=2, A=4. So (x-2)(x^2+4x+3)=0....

Answered by Maths tutor
2014 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences