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What is 2 1/5 + 1 3/4

First simplify both sides:2 1/5 = 11/5 1 3/4 = 7/4Then find common denominator by multiplying denominators:4/5 = 20Times denominators by opposite denominator (do to top and bottom):7/4 = 35/20 13/5 = 44/2...

HH
Answered by Harry H. Maths tutor
3399 Views

The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

We know the perimiter is split into the proportions 3:4:5 therefore by adding 3+4+5 we can work out what fraction of 72cm each side is.Thus 3/(3+4+5) = 3/12 = 1/4 is the fraction of 72 that belongs to the...

SD
Answered by Sefton d. Maths tutor
10491 Views

Prove cosec2A-cot2A=tanA

Cosec2A - cot2A= tanA
Left hand side=1/sin2A - cos2A/sin2A
=(1- cos2A)/sin2A
=(1-(1- 2 sin^2⁡ A)/ 2sinAcosA
=(1-1 + ( 2 sin^2⁡ A))/ 2sinAcosA
=sinA/cosA
=tanA
Therefore ...

ST
Answered by Sherin T. Maths tutor
12805 Views

3n+2 <= 14 and 6n/(n^2+5) > 1 Find possible values of N

3n+2 is less then or equaled to 14. 6n divided by N squared + 5 is less then 1. First, we are going to deal with the equation on the left. From this equation, takeaway 2 from both sides to get 3n<=12, ...

MA
Answered by MOHAMMAD A. Maths tutor
3496 Views

A curve is defined by parametric equations: x = t^(2) + 2, and y = t(4-t^(2)). Find dy/dx in terms of t, hence, define the gradient of the curve at the point where t = 2.

dy/dx = (dy/dt)/(dx/dt) y = t(4-t2 ), then using differentiation of y with respect to t, dy/dt = 4 - 3t2x = t2 + 2, then...

MW
Answered by Micah W. Maths tutor
4986 Views

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