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The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

We know the perimiter is split into the proportions 3:4:5 therefore by adding 3+4+5 we can work out what fraction of 72cm each side is.Thus 3/(3+4+5) = 3/12 = 1/4 is the fraction of 72 that belongs to the...

Answered by Sefton d. • Maths tutor

8827 Views

Prove cosec2A-cot2A=tanA

Cosec2A - cot2A= tanA
Left hand side=1/sin2A - cos2A/sin2A
=(1- cos2A)/sin2A
=(1-(1- 2 sin^2⁡ A)/ 2sinAcosA
=(1-1 + ( 2 sin^2⁡ A))/ 2sinAcosA
=sinA/cosA
=tanA
Therefore ...

Answered by Sherin T. • Maths tutor

11144 Views

3n+2 <= 14 and 6n/(n^2+5) > 1 Find possible values of N

3n+2 is less then or equaled to 14. 6n divided by N squared + 5 is less then 1. First, we are going to deal with the equation on the left. From this equation, takeaway 2 from both sides to get 3n<=12, ...

Answered by MOHAMMAD A. • Maths tutor

2913 Views

A curve is defined by parametric equations: x = t^(2) + 2, and y = t(4-t^(2)). Find dy/dx in terms of t, hence, define the gradient of the curve at the point where t = 2.

dy/dx = (dy/dt)/(dx/dt) y = t(4-t²), then using differentiation of y with respect to t, dy/dt = 4 - 3t²x = t² + 2, then...

Answered by Micah W. • Maths tutor

4455 Views

Solve x^2 - 6x + 8 < 0

To see the answer more clearly, we can sketch the function. First, we start by sketching the parabola (curve). If we have a positive x^2 term then we have a U shaped parabola and if it is negative, i.e. -...

Answered by Rachel W. • Maths tutor

11244 Views