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Pythagorus' theorem a^2 + b^2 = c^24^2 + 5^2 = c^216+25 = c^241 = c^2Root 41 or 6.403 = c
i) let dy/dx = ans, where ans = y, where you multiply the coefficients of each constant of x by the power and reduce the power by 1 in the equation ytherefore dy/dx = 2x - 2 - 12x-1/2ii) repeat...
To work out the mean, we first add up all of the scores so 4+4+7+3+9+10+5+8= 50. We then divide by the number of student who took the test, or the number of scores given, which is 8. Divide 50 by 8 to giv...
Use factorisation to solve this. You must find a pair of numbers that add to make 6 and multiply to make 5. In this question, 5 and 1 add to make 6 and they also multiply to make 5. So the factorised equa...
a) First we can rewrite y=arccos(x/2) as cosy = x/2 which allows us to use implicit differentiation to easily differentiate each side. Taking d/dx of each side gives u...
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