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Find the roots of the following quadratic equation: x^2 +2x -15 =0

The question asks for the roots, this simply means the numbers that could replace x in the equation and the result = 0. There are two ways too do this, firstly either using the Quadratic formula, or my fa...

Answered by Maths tutor
3878 Views

How do you solve a quadratic equation?

For example x2 - 2x - 35 = 0You would have two approaches to this question. You can either use the quadratic formula or you could simplify the expression. Using the formula you would have x = (...

BT
Answered by Bianka T. Maths tutor
2698 Views

Workout 2 1/7 + 1 1/4

Question: 2 1/7 + 1 1/4. Step 1: Rewrite the calculation to simplify (Combine integers) = 2+1+(1/7)+(1/4)=3+(1/7)+(1/4) Step 2: Find the lowest common factor of 4 and 74 ...

SS
Answered by Sam S. Maths tutor
6625 Views

Consider the function f (x) = (2/3) x^3 + bx^2 + 2x + 3, where b is some undetermined coefficient: (a) find f'(x) and f''(x) and (b) if you know that f(x) has a stationary point at x = 2, use this information to find b.

(a) We have f(x)=(2/3)x3+ bx2 + 2x +3. First we have to solve for f'(x)=(dy/dx)f(x) which gives:f'(x) = [(32)/3]x2 + 2bx + 2 <=> f'(x)=2x2+ 2bx + 2 Fr...

Answered by Maths tutor
3059 Views

x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both si...

JP
Answered by Jai P. Maths tutor
2915 Views

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