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4(3x-7) = 8

First multiply out the bracketsMultiply each component within the bracket by 4 (4 x 3x) + (4 x -7) = 812x - 28 = 8 Now you want to ensure you have the x's on their ownYou can eliminate the -28 by adding 2...

Answered by Jack H. Maths tutor
1621 Views

Solve by completing the square: x^2 + 12x + 4 = 0

(x+6)^2-36+4=0(x+6)^2-32=0(x+6)^2=32(x+6)=±√32x=-6±√32

Answered by Elisha K. Maths tutor
2162 Views

Simplify the following equation: x^(2) +3x+4^(2)-2

In order to simplify the equation, like terms need to be collected.Square terms (x2) can’t be collected with not square terms (x).
x2 terms = 1x2 + 4x2 = 5...

Answered by Marie A. Maths tutor
2112 Views

How do I solve simultaneous equations that aren't linear, for example x^2 + 2y = 9, y = x + 3

First, let's start by labelling the equations. We can call x2+2y=9 equation 1 and y=x+3 equation 2. Rearrange equation 2 to give us x = y-3. We can then substitute this back into equation 1. So...

Answered by Esther M. Maths tutor
1930 Views

If f(x) = x^2, draw the graph of y = f(x) + 3

We can first draw the graph of y = f(x) = x^2 which is a simple graph like this (whiteboard). Now looking at y = f(x) + 3, we can see that this is a translation by the vector [0 3]. Therefore we can tr...

Answered by Maisie S. Maths tutor
2619 Views

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