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Why does the translation y=f(x+2) translate the graph f(x) 2 units left instead of 2 to the right?

It seems like f(x+2) should translate the graph y=f(x) 2 to the right, it is +2 inside the bracket after all? However, if we think of the translation as actually subbing in x+2 into the equation y=f(x), i...

SH
Answered by Seth H. Maths tutor
10457 Views

Express 4x/(x^2-9)-2/(x+3) as a single fraction in its simplest form

4x/(x2-9)-2/(x+3) = 4x/((x+3)(x-3))-2/(x+3) = 4x/((x+3)(x-3))-2(x-3)/((x+3)(x-3)) = (4x-2(x-3))/((x+3)(x-3)) = (2x+6)/((x+3)(x-3) = (2(x+3))/((x+3)(x-3)) = 2/(x-3)

CS
Answered by Charles S. Maths tutor
8695 Views

Find the equation of the normal to the curve y=2x^3 at the point on the curve where x=2. Write in the form of ax+by=c.

For x = 2, y = 16. Calculate the gradient of the curve at y = 2, dy/dx = 6x^2, dy/dx = 24. This is also the gradient of the tangent to the curve at x = 2. It is a rule that the products of the gradients o...

ML
Answered by Maddy L. Maths tutor
9267 Views

Given that y=π/6 at x=0 solve the differential equation,dy/dx=(e^x)cosec2ycosecy

This question challenges a students skills with integration and trigonometry a very common question on Core 4 papers that can leave students struggling. First we use our knowledge that cosecy=1/siny and m...

OL
Answered by Oliver L. Maths tutor
12945 Views

Find the area enclosed between C, the curve y=6x-x^2, L, the line y=16-2x and the y axis.

First we need to find the intersection point(s) of L and C so set 6x-x2=16-2x and rearrange to get x2-8x+16=0 so (x-4)2=0.Repeated root so line is tangent to the curve at ...

DM
Answered by David M. Maths tutor
3751 Views

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