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When dealing with a linear and quadratic simultaneous equation, it is best to use subsitution to approach it.I take the linear equation and put it in terms of one variable. In this case, to avoid fraction...

If the question is about something losing value, for example a cars value depreciates at a rate of 30% a year after 4 years how much will the car be worth? You are also given that at year 0 it was worth £...

Differentiate the equation.Let the derivative equal to 0 and get x.Substitute the value of x into the original equation to get y.

a) 54-45+3a+18=0 3a+27=0 3a=-27 and thus a=-9b) 2x^3 – 5x^2 -9x + 18 = (x-3) (2x^2 +bx-6)to find b ; collect the x^2 terms so bx^2-6x^2=-5x^2 and thus b=1c) when comparing f(y) and f(x) we see ...

e^{x^2} --------> dy/dx = 2xe^{x^2}