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How can you solve an equation with unknowns in the denominators?

First, you should make it so that each fraction has a common denominator. This will usually be done by multiplying the numerator and the denominator of the fraction by the same expression (this is accepta...

Answered by Joshua R. • Maths tutor

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ln(2x^2 + 9x – 5) = 1 + ln(x^2 + 2x – 15). Express x in terms of e

ln(2x²+ 9x – 5) = 1 + ln(x² + 2x – 15)ln(2x²+ 9x – 5) – ln(x² + 2x – 15)= 1 ln((2x²+ 9x – 5)/(x² + 2x – 15)) = 1(2x²+ 9x – 5)/(...

Answered by Sylvain F. • Maths tutor

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express (1+4(root7)) / (5+2(root7)) as a+b(root7), where a and b are integers

1+4(root7) x 5 - 2(root7)5+2(root7) 5 - 2(root7)5 - 2(root7) + 20(root7) - (8x7) 25 - (4x7)5 +18(root7) - 56 -3-51 + 18(root7) -317 - 6(root7)ie a = 17, b = -6

Answered by Hannah B. • Maths tutor

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