Search our library of Maths questions

Top answers

Maths

All levels

Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

y = x³- 2xdy/dx = 3x²-2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y₁=m(x - x₁)substitute y₁=4 and ...

Answered by Kevalee S. • Maths tutor

5143 Views

The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.

First of all, you are trying to prove that these two lines are parallel. So how would we be able to show this… Well two lines are parallel to one another if they have the same gradient (draw demonstration...

Answered by Emily H. • Maths tutor

2873 Views

I always mix up my integration and differentiation. How do i stop this?

First thing to do is practice. Practice makes perfect. You are not going to get through your differentiation and integration by doing only a couple of questions on these topics. You need to take one topic...

Answered by Yasmin P. • Maths tutor

3887 Views

Find dy/dx for (x^2)(y^3) + ln(x^y) = 5sin(6x)/x^(1/2)

To differentiate this equation we must use the implicit method, looking at the left side of the equation, to find the differential of the first term we must use the product rule, therefore the differentia...

Answered by Max H. • Maths tutor

3198 Views

Solve algebraically the simultaneous equations x^2 +y^2 =25, y – 3x = 13

This question is done by substituting either the x or y. To do this, rearrange the second equation to make y the subject. We make y the subject as it keeps the equation and calculation simple. After rearr...

Answered by Shun S. • Maths tutor

20475 Views