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How do you find the turning point of a parabola using its equation? using its equation?

First, you have to differentiate the equation to find the first derivative. Once you do this, you then set the derivative to equal zero and find the corresponding x value. This number is the x-value of th...

Answered by Ifeoluwa Y. Maths tutor
2814 Views

Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.

To satisfy the condition of substracting two fractions with unlike denominators, a common denominator needs to be found. By recognizing x^2 - 9 = (x-3)(x+3), we can rewrite the question as 4x/(x-3)(x+3) -...

Answered by Ye C. Maths tutor
5571 Views

Show that r^2(r + 1)^2 - r^2(r - 1)^2 ≡ 4r^3.

Start with the left hand side (LHS) of the equation. r^2(r + 1)^2 - r^2(r - 1)^2Take the equivalent terms from the separate parts of the LHS outside of set of brackets.r^2[(r + 1)^2 - (r - 1)^2]Expand t...

Answered by Andrew D. Maths tutor
6480 Views

Solve the simultaneous equations 8x+2y=34 and 4x+2y=18

1.Simplify the two equations: 4x+y=17and 2x+y=9. 2. Rearrange one of the equations to make y=: y=9-2x. 3.Substitute into other equation:4x+9-2x=17. 4. Simplify:2x=8 x=4. 5.Substitute back into either of t...

Answered by Lara M. Maths tutor
3147 Views

Two particles, A and B, are moving directly towards each other on a straight line with speeds of 6 m/s and 8 m/s respectively. The mass of A is 3 kg, and the mass of B is 2 kg. They collide to form a single particle of speed "v" m/s. Find v.

The student should apply their knowledge of conservation of momentum. Also, I would always encourage the student to draw a diagram for all mechanics questions as it helps visualise the problem.total chang...

Answered by Kieran H. Maths tutor
4004 Views

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