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The equation of the line L1 is: y = 5x-4. The equation for line L2 is 2y-10x+16 = 0. Show that these two lines are parallel.

L1: y=5x-4L2: 2y-10x+16=0. Rearranged: 2y=10x-16, y=5x-8 The coefficient of x is the same in both equations when expressed in standard format (5), therefore the lines are parallel.

Answered by Alfie W. Maths tutor
4541 Views

How do I calculate the eigenvalues and eigenvectors of a 2x2 matrix, and what is the point of doing this calculation?

We find the eigenvalues (here called "k") by solving the characteristic equation det(M - kI) = 0. For a 2x2 matrix ((a, b), (c,d)) the determinant is ad - bc, we set this equal to zero ...

Answered by Tutor120184 D. Maths tutor
3455 Views

Find the derivative of y=e^(2x)*(x^2-4x-2).

Notice that y can be expressed as y=f(x)g(x), in which f(x)=e^(2x) and g(x)=x^2-4x-2.Through the product rule, we know that dy/dx=f'(x)g(x)+f(x)g'(x).Through the chain rule, we can solve f(x) by rewriting...

Answered by Samuel H. Maths tutor
7721 Views

Solve x^2+4x-5=0

Two approaches.1.Note that the equation is a quadratic equation, and can thus be solved per the quadratic formula, in which the solutions are given to be (-b+-sqrt(b^2-4ac))/2a.Plugging in the values from...

Answered by Samuel H. Maths tutor
3557 Views

Solve the equation: x^2 +8x + 12 = 0

This is a classic GCSE-style equation :)
1) Always write out the original equation for clarity (and so that you don't have to look back at the question constantly) :)x^2 + 8x + 12 = 02) Notice that t...

Answered by Obaid U. Maths tutor
4596 Views

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