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L1: y=5x-4L2: 2y-10x+16=0. Rearranged: 2y=10x-16, y=5x-8 The coefficient of x is the same in both equations when expressed in standard format (5), therefore the lines are parallel. Answered by Alfie W. • Maths tutor4541 Views
We find the eigenvalues (here called "k") by solving the characteristic equation det(M - kI) = 0. For a 2x2 matrix ((a, b), (c,d)) the determinant is ad - bc, we set this equal to zero ...
Notice that y can be expressed as y=f(x)g(x), in which f(x)=e^(2x) and g(x)=x^2-4x-2.Through the product rule, we know that dy/dx=f'(x)g(x)+f(x)g'(x).Through the chain rule, we can solve f(x) by rewriting...
Two approaches.1.Note that the equation is a quadratic equation, and can thus be solved per the quadratic formula, in which the solutions are given to be (-b+-sqrt(b^2-4ac))/2a.Plugging in the values from...
This is a classic GCSE-style equation :)1) Always write out the original equation for clarity (and so that you don't have to look back at the question constantly) :)x^2 + 8x + 12 = 02) Notice that t...
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