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The stationary point is a minimum point. I will run through the working out for the question using the whiteboard in the session as it is difficult to demonstrate without relevant formatting.

This requires use of the quotient rule: d/dx[f(x)/g(x)] = [g(x)f'(x) - g'(x)f(x)]/[g(x)^2]dy/dx = ([(3x-1)*2x] - 3x^2)/[(3x-1)^2],= (3x^2-2x)/[(3x-1)^2],=[x(3x-2)]/[(3x-1)^2]

y = x³ - 3x² - 24x + 5, First, calculate the derivative of y and find its roots when y = 0:dy/dx = 3x² - 6x -24 = 0 -> x² - 2x - 8 = 0 -> (x+2)(x-4) = 0Th...

When finding the gradient of a line we need to first locate any two points, on the line, where we know the x-coordinates and we know the y-coordinates. Now, with these two coordinates we need to find two ...

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