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Let u=exp(2x) and v'=cos(8x)From these you can obtain u' and vu=2exp(2x) and v=1/8 sin(8x)Formula: integral(uv'dx)=uv-integral(vu'dx)=1/8 exp(2x)sin(8x)-integral(1/4 sin(8x)exp(2x))=1/8exp(2x)sin(8x)+1/16...

The first thing to recognise is this is a quadratic in disguise, therefore we can rewrite the equation in terms of a new variable y.
Where y=x³
The equation then becomes 8y²

Since the question is a trigonometry question, we shall use integration by recognisation, in which case, we found out that the derivative of sin x is cos x.Therefore by chain rule, we can integrate the fu...

To solve this question we need to find the values of x which work for the equation x^(2) + 4x + 4 = 0. To solve the equation we can factorise the left-hand side into brackets which will m...

Remember we can multiply both sides of an equation by the same thing without changing the meaning of the equation. Multiplying equation 1 by 2 gives 4x+6y=6 and multiplying equation 2 by 3 gives 9x+6y=21 ...