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Solve the quadratic equation, x^2 - 4x -5 = 0

Solve x2- 4x - 5 = 0
A very full explanation would be:
Start by listing the pairs of numbers that can be multiplied together to get 1 * -5 = -5 (i.e. the coefficient of the first ter...

Answered by Ryan H. Maths tutor
3908 Views

Solve for y and x, where x=y+1 and y=2x+3

Simultaneous equations:
x=y+1 y=2x+3
First solve for x. y=2x+3 so first equation becomes: x=(2x+3)+1 x-2x-3-1=0 -1x-4=0x+4=0 x=-4
Solve for y: y=2x+3 y=2(-4)+3 y=-8+3y=-5

Answered by Tom S. Maths tutor
3437 Views

Solve the simultaneous equations 2x + y = 7 and 3x - y = 8

There are three methods for solving simultaneous equations: elimination, substitution and by using graphs.Elimination is a good method in this case as the y terms are equal in both equations. We just add ...

Answered by Tia J. Maths tutor
6670 Views

Prove the change of base formula for logarithms. That is, prove that log_a (x) = log_b (x) / log_b (a).

Firstly, recall the definition of a logarithm: if y = loga(x), then this means that y is the power you have to raise a to, to get x, that is ay = x.Now, we want to introduce a new ba...

Answered by Tom H. Maths tutor
9143 Views

How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x

Answered by Chloe M. Maths tutor
2687 Views

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