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Chemistry

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In terms of Electrostatic Forces, Suggest why the ‘Electron Affinity’ of Fluorine has a Negative value.

Electron affinity is the energy released when 1 mole of gaseous atoms each acquire an electron to form 1 mole of gaseous 1- ions. Fluorine has a negative value as energy is released when the electron i...

Answered by Arthur G. • Chemistry tutor

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The ratio between the molar mass of an alkene(A) and an alkyne(B) with the same number of carbon atoms is 1.05. Find the molecular formulas of the two hydrocarbons then write the reaction for how we can obtain the alkene A from the alkyne B.

We start by remembering the general formulas of alkenes and alkynes:
Alkenes - C_nH_2n
Alkynes - C_nH_2n-2
We calculate the molar mass of both of the...

Answered by Cosmin B. • Chemistry tutor

9022 Views

Why do transition metals form coloured solutions?

White light is a mixture of different colours of light (e.g red, green and blue) and each colour has a different wavelength. For something to have colour, it needs to absorb certain wavelengths...

Answered by Yusuf B. • Chemistry tutor

11231 Views

At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.
When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0, T = ΔH / ΔS.

Must convert ΔS from JK^-1mol^-1 to ...
Answered by Lily W. • Chemistry tutor
18755 Views

How is the electrophile formed for the nitration of benzene??
React concentrated sulfuric acid with concentrated nitric acid in the below reaction to yield the nitronium ion.

HNO₃ + 2H₂SO₄ --> NO<...
Answered by Jessie D. • Chemistry tutor
4848 Views

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In terms of Electrostatic Forces, Suggest why the ‘Electron Affinity’ of Fluorine has a Negative value.

The ratio between the molar mass of an alkene(A) and an alkyne(B) with the same number of carbon atoms is 1.05. Find the molecular formulas of the two hydrocarbons then write the reaction for how we can obtain the alkene A from the alkyne B.

Why do transition metals form coloured solutions?

At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.

How is the electrophile formed for the nitration of benzene??

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