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Maths
A Level

A Curve has parametric equation x=2sin(t), y= 1+cos(2t), -pi/2<=t<=pi/2. a) Find dy/dx when t=pi/3. b) Find the Cartesian equation for the curve in form y=f(x), -k<=x<=k. c) Find the range of f(x)

x=2sin(t), y=1+cos(2t)

a) By chain rule, dy/dx = (dy/dt)/(dx/dt)
dy/dt = -2sin(2t), dx/dt= 2cos(t)
dy/dx= -sin(2t)/cos(t)
dy/dx=-2sin(t)cos(t)/cos(t)
dy/dx=-2sin(t)

Answered by Max B. Maths tutor
9829 Views

Find the first and second derivatives of: y = 6 - 3x -4x^-3, and find the x coordinates of the line's turning points

dy/dx = -3 +12x^-4 d^2y/dx^2 = -48x^-5

Answered by Matthew S. Maths tutor
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Integrate 2sin(theta)cos(2*theta)

cos(theta)-(4/3)cos3(theta)

Answered by Chloe B. Maths tutor
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The curve C has the parametric equations x=4t+3 and y+ 4t +8 +5/(2t). Find the value of dy/dx at the point on curve C where t=2.

a) What can we find from what we have been given?

dx/dt and dy/dt

How can we relate these values to dy/dx?

In the context of equations that only contain two variables, their derivativ...

Answered by Chloe B. Maths tutor
8820 Views

Starting from the fact that acceleration is the differential of velocity (dv/dt = a) derive the SUVAT equations.

Intergrating with respect to time, you get that v = u + at. Knowing that velocity is just the rate of change of your position ds/dt = v, and sustituting the previous expression for v, you get ds/dt = u + ...

Answered by Ben W. Maths tutor
5071 Views

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