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Maths
A Level

Using integration by parts, and given f(x) = 3xcos(x), find integrate(f(x) dx) between (pi/2) and 0.

We begin by quoting the integration by parts formula, as the question speciaficaly asks us to use it.

integrate(u(x) v'(x) dx)|^(b)(a) = [u(x) v(x)]^(b)(a) - integrate(u'(x) v(x) dx)|^(b)_...

Answered by Aaron C. Maths tutor
3145 Views

integrate by parts ln(x)/x^3

The question states to use integration by parts. So first we recall the integration by parts formula is integrate(u(x)v'(x)  dx)=     (v(x)u(x))    -    integrate(u'(x)v(x)   dx)+c...

Answered by Prit S. Maths tutor
3119 Views

Given that the equation of the curve y=f(x) passes through the point (-1,0), find f(x) when f'(x)= 12x^2 - 8x +1

Firstly, Integrate the f'(x) equation by raising the power by 1 and then dividing by the new power and adding a constant c. This gives you f(x)=(12x^3)/3 -(8x^2)/2 + x + c Then you simplify, f(x)=4x^3 -4x...

Answered by Daniel M. Maths tutor
12980 Views

If f(x)= ( ((x^2) +4)(x-3))/2x find f'(x)

Tackle differentiation questions in two parts: First put it into the simplest for possible for differenciation, then perform the differenciation. 

So for this equation you should first expand the t...

Answered by Alex B. Maths tutor
3308 Views

Find tan(A-B) sec^2(A) - 2tan(A) = 16 && sin(B)sec^2(B) = 64cos(B)cosec^2(B)

@tan(A) = 5, tan(B) =4, tan(A - B) = 1/21

@tan(A) = -3, tan(B) = 4, tan(A - B) = 7/11

I can demonstrate how the answers can be obtained during the session.

Answered by Fedor S. Maths tutor
2858 Views

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