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It can seem tricky to integrate ln(x), as there is no obvious solution to do it.It is, however, quite simple to do if you use the 'by parts' method.If you have y=ln(x)Set u=ln(x) and dv/dx=1That gives du/...
Stationary point: dy/dx = 2e^2x - 11e^x =0 2e^2x = 11e^xe^x=5.5 (can divide by e^x since e^x > 0 for all x)x=ln(5.5), y=5.5^2-115.5+24=-6.25Answer: Answered by Asmita J. • Maths tutor2663 Views
When differentiating an equation (y) you find the equation of the gradient, called dy/dx. The rule for differentiating a power of x is given below:y=x^n dy/dx= nx^(n-1)Applying this rule to this question ...
The very first step in solving this problem is understanding that a stationary point is where the derivative of the curve, dy/dx (or in Newton’s notation y’), is equal to zero. This is because at stationa...
Quotient rule: d(u/v)/dx = [(du/dx)v-u(dv/dx)]/v^2u = ln(3x) v = e^4xFind du/dx using chain rule: u = ln(z) ==> du/dz = 1/z z = 3x ==> dz/dx = 3 (du/dz)(dz/dx) = ...
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