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Maths
A Level

How would you integrate ln(x)

It can seem tricky to integrate ln(x), as there is no obvious solution to do it.It is, however, quite simple to do if you use the 'by parts' method.If you have y=ln(x)Set u=ln(x) and dv/dx=1That gives du/...

Answered by Adam C. Maths tutor
2535 Views

y=e^2x-11e^x+24 Find the stationary point, nature of the stationary point, the x-intercepts and the y-intercept (calculator allowed)

Stationary point:
dy/dx = 2e^2x - 11e^x =0
2e^2x = 11e^x
e^x=5.5 (can divide by e^x since e^x > 0 for all x)
x=ln(5.5), y=5.5^2-115.5+24=-6.25
Answer:

Answered by Asmita J. Maths tutor
2663 Views

What is the gradient of this curve y=5x^3+6x^2+7x+8 at point x=3?

When differentiating an equation (y) you find the equation of the gradient, called dy/dx. The rule for differentiating a power of x is given below:y=x^n dy/dx= nx^(n-1)Applying this rule to this question ...

Answered by Tutor179115 D. Maths tutor
3682 Views

A curve has an equation y=3x-2x^2-x^3. Find the x-coordinate(s) of the stationary point(s) of the curve.

The very first step in solving this problem is understanding that a stationary point is where the derivative of the curve, dy/dx (or in Newton’s notation y’), is equal to zero. This is because at stationa...

Answered by Callum G. Maths tutor
4051 Views

Use the quotient rule to differentiate: ln(3x)/(e^4x) with respect to x.

Quotient rule: d(u/v)/dx = [(du/dx)v-u(dv/dx)]/v^2
u = ln(3x)
v = e^4x
Find du/dx using chain rule:
u = ln(z) ==> du/dz = 1/z
z = 3x ==> dz/dx = 3
(du/dz)(dz/dx) = ...

Answered by Henry T. Maths tutor
3720 Views

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