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The first step is to factorise the equation into two brackets. In this case we get (2x+1)(x-6)Now, for this to be greater than zero we need both brackets to be greater than zero, or both brackets to be le...

First combine the x-parts of the equation: 4x - 2x = 2x Next move the "number parts" so they are all on the same side: 2x + 8 = 10 ---> 2x = 2 Then divide through by 2 to move the 2 from the...

Completing the square is nice and easy. If you have an equasion of the form x²+ax+b=0 then simply rewrite the equasion in the form (x+a/2)²-(a/2)² +b=0. This may sound com...

3(x+4) - 2(4x+1)= 3x + 12 - 8x + 2= 3x - 8x + 12 - 2= -5x + 10

Quadratic equations take the form ax^2 + bx + c = 0. In the case above, a = 0, b = -5, c = -14. In order to solve it, we can factorise the equation into the form (x+c)(x+d) = 0. The answers are then x = -...