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Maths
GCSE

Solve the following quadratic equation: 2x^2 - 5x - 3 = 0

Firstly, we need to factorise the equation:We can see (and are told) that the equation is quadratic and is therefore of the form ax^2 + bx + c. In our case, a=2, b=-5 and c=-3. We therefore expect two pai...

Answered by Jacob A. Maths tutor
3609 Views

Solve the quadratic equation 4x^2 - 5x -6 = 0

First factorise the equation : you need to find two value which multiply to give (4 x -6) = -24 and add to equal -5,these two numbers are -8 and 3. Then write the equation as follows:4x2 - 8x...

Answered by Katie S. Maths tutor
6456 Views

Expand and simplify 4x(x+3) - (2x-3)2

When dealing with such a question, an expansion question, the first part of the equation to look at is the brackets.Looking at the question above, one can see that there are two pairs of brackets - it wou...

Answered by Tofi O. Maths tutor
7532 Views

Solve the simultaneous equations: 2x+2y = 10 and 7x + 4y = 26

The first step with any simultaneous equation is to cancel out one of the variables. Here, 2y is a factor of 4y (it fits into 4y twice) so we can multiply the 1st equation by 2 to give us 4x+4y = 20.This ...

Answered by Sylvia M. Maths tutor
4231 Views

Solve the simultaneous equations: 2x-3y = 16 x+2y= -6

x=2 y=-4

Answered by Nadia A. Maths tutor
2805 Views

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