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Maths
GCSE

Find the value of x that satisfies the following equation: (3x + 2)/2 = 6x + 4

Step 1: Eliminate fractions => Multiply everything by 23x + 2 = 12x + 8 Step 2: Collect like-terms with all of the xs on one side => 9x = -6 Step 3: Divide through to find the answer in terms of x...

Answered by Jacob P. Maths tutor
2866 Views

I struggle with the following type of question: "The first four terms of an arithmetic sequence are 5, 9, 13, 17. Write down an expression, in terms of n, for the nth term in the sequence." How should I approach this?

The way I would suggest approaching a question like this is to imagine n=1, n=2, n=3 and n=4 above the terms given, or even to literally write that above each of the 4 given numbers. n ---------- 1 2 3 4r...

Answered by William S. Maths tutor
9620 Views

√3(√30 + √8) can be simplified into the follwing format: x√10 + y√6 where are x and y are integers. Find the value of x and y.

Begin by expansion (√a x √b = √ab): √3 x √30 = √90 and √3 x √8 = √24. Therfore we have: √90 + √24. Simplify roots (√a^2√b). The question tells us we need x√10 so therefore √90 = √9√10 (9x10 = 90) and we n...

Answered by Holden D. Maths tutor
3602 Views

P has coordinates (3,4), Q has coordinate (a,b), a line perpendicular to PQ has equation 3x+2y=7. Find an expression for b in terms of a

Rearrange the equation of the line perpendicular to PQ to give y = -(3/2)x + 7/2. Gradient of this line = -3/2Using the knowledge that the gradients of a line perpendicular to another line is related by a...

Answered by Jack L. Maths tutor
4069 Views

Solve by factorisation. 2x(^2)+5x-12=0

To factorise and solve for x, open two sets of brackets, i.e: (x )(x ). For this question note than one x should be replaced by 2x such that (2x )(x ). List the pairs of numbers that give a product of 12,...

Answered by Emily W. Maths tutor
6273 Views

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