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Solve sec(x)^2-2*tan(x)=4 for 0<=x<=360

We know sin(x)^2+cos(x)^2=1Dividing by cos(x)^2: tan(x)^2+1=sec(x)^2Substitute into the Equation and Rearrange to get: tan(x)^2-2*tan(x)-3=0Let y = tan(x): y^2-2y-3=0Factorising: (y-3)(y+1)=0so y = 3 and ...

Answered by Mukesh R. Maths tutor
3377 Views

y is inversely proportional to x. y = 0.04 when x = 80. Find the value of y when x = 32.

If y is inversely proportional to x. We know that y=k/x for some constant k. We need to find this constant before continuing. Looking at the information given to us in the question we know for one example...

Answered by Tyler T. Maths tutor
5721 Views

solve the simultaneous equations 8x + 2y = 48 , 14x + 6y = 94

Step 1) Rearrange the first equation to make y the subject: 8x + 2y = 48 , 2y = 48 - 8x , y = 24 - 4x. step 2) Sub y = 23 - 4x into the second equation: 14x + 6(24 -4x) = 94 , 14x + 144 - 24x = 94 Step 3)...

Answered by Harrison S. Maths tutor
2401 Views

The second and fourth term of a geometric series is 100 and 225 respectively. Find the common ratio and first term of the series. Round your answer to 2 d.p if necessary

Formula for a Geometric series for term n = arn , where a = the first term and r = common ratio.Therefore, with the information given we can write that ar2 = 100 and ar4 =...

Answered by Maths tutor
2959 Views

Find the area contained under the curve y =3x^2 - x^3 between 0 and 3

Equation of curve is: y = y =3x2 - x3To find area need to integrate between 0 and 3So integrating each term gives x3 - x4/4 + ...

Answered by Juan R. Maths tutor
2100 Views

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