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Maths
GCSE

Mixed rugby team of 20, 5 are female. 15 play at a time. i.) What is the percentage chance of a female playing. ii.)A minimum of three females must now be on the pitch. What is the percentage chance of 4 females playing?

i.) 5/20 * 15/20 *100 = 18.755%ii.) Since 3 have to be on the team, essentially the problem is percentage chance of one female getting onto a team of 12, therefore 2/17 * 12/17 * 100 = 8.30%

Answered by Alfie C. Maths tutor
1921 Views

f(x) = (2x+3)/(x-4). Work out f^-1 (x)

f-1(x) = inverseSet f-1(x) as y = (2x+3)/(x-4)y(x-4) = 2x+3yx-4y = 2x+3yx-2x = 3+4yx(y-2) = 3+4yx = (3+4y)/(y-2)f-1(x) = (3+4x)/(x-2)

Answered by Gurlina H. Maths tutor
4544 Views

For which values of x is x^2 - 5x + 6 < 0 true?

Factorising the left hand side of the inequality gives (x-2)(x-3), so we know that the quadratic curve intersects the x-axis at x=2 and x=3. Since the coefficient of x^2 in the quadratic equation x^2-5x+6...

Answered by Thomas V. Maths tutor
13424 Views

Find the equation of the straight line which passes through the points (5, 0) and (6, 4).

We can use the general equation of a straight line to tackle this question: y=mx+c (m is the gradient and c is the y-intercept).(Note: The points are in the form (x, y).)
First, we will determine the...

Answered by Chloe M. Maths tutor
3716 Views

x : y = 11 : 3 x + y = 140 Find x and y

x = 110y = 30From x: y = 11:3 we can rearrange to find x = 11y/3 or y = 3x/11We can then substitute into x + y = 140 to get 11y/3 + y = 14y/3 = 140 y/3 = 10 y = 30once we have y, we can find that x + 30 =...

Answered by Jake O. Maths tutor
2737 Views

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