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Maths
GCSE

Solve the following simultaneous equations: y - 2x = 6 and y + 2x = 0

Firstly, label each of our equations: y - 2x = 6 (1) y + 2x = 0 (2)Then we can rearrange (2) to get the following: y = -2x (3)Then, substitute (3) into (1): -2x - 2x = 6Which yields the result: -4x = 6The...

Answered by Ciara C. Maths tutor
3533 Views

Suppose we have a circle with the equation x^2 +y^2 =25. What is the equation to the tangent to the circle at point (4,3)?

Firstly lets draw it out-Draw a line from the origin to the point. calculate the change in y over change in x =(3-0)/(4-0)=3/4Take negative reciprocal which is equal to m. Then do y-y1=m(x-x

Answered by Nayan M. Maths tutor
2299 Views

Paul buys three pens and one pencil for £11 while Sam buys four pens and two pencil for £16 - what is the price of pens and pencils?

Read the question and translate the information into equations.'Three pens and one pencil for £11' can be written as 3x + y = 11 where x = pens and y = pencils. 'Four pens and two pencils for £16' can be ...

Answered by Isabelle S. Maths tutor
2057 Views

How do I solve a quadratic equation?

In a quadratic equation the highest power is 2. This means that we are looking for up to 2 answers. The first thing we are going to try to do is factorise the equation. We draw two sets of brackets side b...

Answered by Leszek W. Maths tutor
2201 Views

Simplify (m-7)(m+3)/6(m+3)

Find the highest common factor between the brackets and then divide by this:in this case it is (m+3)so working out should look like this:(m-7)(m+3)/(m+3)/6(m+3)/(m+3)this will work out as:m-7/ 6

Answered by Molly F. Maths tutor
2361 Views

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