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Maths
GCSE

A (0,2) and B (6,5) are points on the straight line ABCD. AB=BC=CD. Work out the co-ordinates of D.

D= (18,11)

AC
Answered by Arianna C. Maths tutor
3844 Views

Point A has coordinates (-1,3). Point B has coordinates (2,-3). Find the equation of the line L that goes through these two points. Point C has coordinates (0,1). Hence or otherwise, find the equation of the line perpendicular to L that goes through C.

First we use the equation gradient = (y1-y2)/(x1-x2) to find the gradient of the line L, using point A (-1,3) and point B (2,-3). This gives us gradient = (3-(-3)/(-1-2) = (3+3)/(-3) = -2. Now we subst...

AG
Answered by Asa G. Maths tutor
3652 Views

Why doesn't (a+b)^2 = a^2+b^2

(a+b)2 actually means (a+b)x(a+b) and so you have to solve this the long way unfortunately. You can use the grid method to do this [I would write this out on the whiteboard function at this poi...

MT
Answered by Mai T. Maths tutor
3075 Views

Solve the following simultaneous equations: y - 2x = 6 and y + 2x = 0

Firstly, label each of our equations: y - 2x = 6 (1) y + 2x = 0 (2)Then we can rearrange (2) to get the following: y = -2x (3)Then, substitute (3) into (1): -2x - 2x = 6Which yields the result: -4x = 6The...

CC
Answered by Ciara C. Maths tutor
4696 Views

Suppose we have a circle with the equation x^2 +y^2 =25. What is the equation to the tangent to the circle at point (4,3)?

Firstly lets draw it out-Draw a line from the origin to the point. calculate the change in y over change in x =(3-0)/(4-0)=3/4Take negative reciprocal which is equal to m. Then do y-y1=m(x-x

NM
Answered by Nayan M. Maths tutor
3154 Views

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