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This is a question based on the application of Pythagoras. In the question a diagram of the triangle ABC will be provided and we would be able to see that we would need to work out the hypotenuse. Thus us...

y=x^2+5x+4 y=-3x-8 Equate the two equations: x^2+5x+4 = -3x-8Rearrange so that all values are on one side: x^2+8x+12=0 Factorise the equation by finding...

first of all, have a look at each side separately to see you you can cancel anything down.e.g. the square and square root can cancel out. => sq.root(6²+8²) = 6+8on the otherside, ...

27^-2/31/(27^2/3)1/(27^1/3)²1/3²= 1/9

To find 125^1/3 we have to solve x³ = 125 => This gives x=5 Then we have 2^-3 is equal to 1/(2³) => This is equal to 1/8So to answer the question we have 5*...