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Maths
GCSE

solve 4(x)^2 -19x - 5 =0

The purpose of this question is find values of x when y = 0 in the graph (ie when the curve crosses the x axis) There are 2 steps for this: 1) factorise the quadratics equation (2) solve for x

Answered by Arslan G. Maths tutor
2725 Views

Solve the following quadratic equation x^(2)+7x+12

(x+a)(x+b) = 0The two numbers must have a product of 12 and a sum of 7.3*4 = 12 AND 3+4=7Therefore(x+3)(x+4) = 0Therefore x+3 = 0 --> x = -3OR x+4 = 0 --> x = -4

Answered by Michael V. Maths tutor
2347 Views

How do I rewrite algebraic fractions as a single fraction?

The first step to writing an expression with more than one fraction as a single fraction is to find their lowest common denominator. For example, in a question with two fractions where the denominators ar...

Answered by David O. Maths tutor
10465 Views

the function f is such that f(x)=(2x-7)/4. Fnd f(-7) and the inverse of the function.

to find the first part we just need to plug in the value-7 in the expression for f replacing our independant value, x .f(-7)=(2*(-7)-7)/4 =(-14-7)/4 =-21/4to find the second part we need to interchange th...

Answered by Emily G. Maths tutor
2366 Views

The equation of the line L1 is y=4x–8. The equation of the line L2 is 3y–12x+4=0. Show that L1 and L2 are parallel.

Parallel lines have the same gradient. The gradient of L1 is 4. For the gradient of L2: 3y=12x-4y=4x-4/3The gradient of L2 is also 4. Thus these lines are parallel.
Explanation 1.Rearrange th...

Answered by Divya P. Maths tutor
2749 Views

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